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TLuaFile: Remove RegisterThread calls since it overrides thread names

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This is due to the horrible design of TLuaFile. Everything may be called
at any time from any thread. FIXME.
This commit is contained in:
Lion Kortlepel
2021-08-15 04:43:11 +02:00
committed by Lion
parent 8ec90d5186
commit 0143748953
1 changed files with 1 additions and 3 deletions
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4
src/TLuaFile.cpp
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@@ -2,6 +2,7 @@
#include "Client.h"
#include "Common.h"
#include "CustomAssert.h"
#include "Defer.h"
#include "TLuaEngine.h"
#include "TNetwork.h"
#include "TServer.h"
@@ -44,7 +45,6 @@ void ClearStack(lua_State* L) {
}
std::any Trigger(TLuaFile* lua, const std::string& R, std::shared_ptr<TLuaArg> arg) {
RegisterThread(lua->GetFileName());
std::lock_guard<std::mutex> lockGuard(lua->Lock);
std::packaged_task<std::any(std::shared_ptr<TLuaArg>)> task([lua, R](std::shared_ptr<TLuaArg> arg) { return CallFunction(lua, R, arg); });
std::future<std::any> f1 = task.get_future();
@@ -198,7 +198,6 @@ void ExecuteAsync(TLuaFile* lua, const std::string& FuncName) {
}
void CallAsync(TLuaFile* lua, const std::string& Func, int U) {
RegisterThread(lua->GetFileName());
lua->SetStopThread(false);
int D = 1000 / U;
while (!lua->GetStopThread()) {
@@ -671,7 +670,6 @@ std::string TLuaFile::GetOrigin() {
}
std::any CallFunction(TLuaFile* lua, const std::string& FuncName, std::shared_ptr<TLuaArg> Arg) {
RegisterThread(lua->GetFileName());
lua_State* luaState = lua->GetState();
lua_getglobal(luaState, FuncName.c_str());
if (lua_isfunction(luaState, -1)) {